4x-(2048/x^2)

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Solution for 4x-(2048/x^2) equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(2048/(x^2)) = 0

4*x-2048*x^-2 = 0

4*x^1-2048*x^-2 = 0

(4*x^3-2048*x^0)/(x^2) = 0 // * x^4

x^2*(4*x^3-2048*x^0) = 0

x^2

4*x^3-2048 = 0

{ 1, -1, 2, -2, 4, -4, 8, -8, 16, -16, 32, -32, 64, -64, 128, -128, 256, -256, 512, -512, 1024, -1024, 2048, -2048 }

1

x = 1

4*x^3-2048 = -2044

1

-1

x = -1

4*x^3-2048 = -2052

-1

2

x = 2

4*x^3-2048 = -2016

2

-2

x = -2

4*x^3-2048 = -2080

-2

4

x = 4

4*x^3-2048 = -1792

4

-4

x = -4

4*x^3-2048 = -2304

-4

8

x = 8

4*x^3-2048 = 0

8

x-8

4*x^2+32*x+256

4*x^3-2048

x-8

32*x^2-4*x^3

32*x^2-2048

256*x-32*x^2

256*x-2048

2048-256*x

0

4*x^2+32*x+256 = 0

DELTA = 32^2-(4*4*256)

DELTA = -3072

DELTA < 0

x in { 8}

x = 8

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